- Local time
- 10:20 AM
- Joined
- May 27, 2015
- Messages
- 6,269
- Reaction score
- 23,902
- Location
- Gaston South Carolina
Are you talking about a metal spacer or a black gasket spacer? Thanks
https://www.amazon.com/Holley-108-12-Carburetor-Base-Gasket/dp/B00029J4KG/ref=sr_1_1?sr=8-1 (https://www.amazon.com/Holley-108-12-Carburetor-Base-Gasket/dp/B00029J4KG/ref=sr_1_1?sr=8-1)Are you talking about a metal spacer or a black gasket spacer? Thanks
Item #1. Heat isolation....depending on what it is made from....the R value or resistance to heat transfer.There are probably at least a few benefits to a spacer, but mainly academic?
1) isolating the carb from heat.
2) it gives the intake charge a more gradual turn into the runner which helps flow.
3) it increases plenum volume.
I used one a long time ago mainly to address concerns regarding heat.
That’s a base gasket not a spacer. And yes, you need that. The choke won’t be set right with out it.
Yeah Wayne, I can’t believe you didn’t know that. ShhhheeeItem #1. Heat isolation....depending on what it is made from....the R value or resistance to heat transfer.
Item #2. It creates a larger pressure drop and REDUCTION of flow velocity of the exiting fuel mixture which actually hinders flow due to the expansion factor....Boyals Law of pressure volume temperature relationships. Applies to fuel induction systems also.....
As per Boyle’s law, any change in the volume occupied by a gas (at constant quantity and temperature) will result in a change in the pressure exerted by it. In other words, the product of the initial pressure and the initial volume of a gas is equal to the product of its final pressure and final volume (at constant temperature and number of moles). This law can be expressed mathematically as follows:
P1V1 = P2V2
Where,
P1 is the initial pressure exerted by the gas
This expression can be obtained from the pressure-volume relationship suggested by Boyle’s law. For a fixed amount of gas kept at a constant temperature, PV = k. Therefore,
- V1 is the initial volume occupied by the gas
- P2 is the final pressure exerted by the gas
- V2 is the final volume occupied by the gas
P1V1 = k (initial pressure * initial volume)
P2V2 = k (final pressure * final volume)
∴ P1V1 = P2V2
This equation can be used to predict the increase in the pressure exerted by a gas on the walls of its container when the volume of its container is decreased (and its quantity and absolute temperature remain unchanged).
Examples of Boyle’s Law
When a filled balloon is squeezed, the volume occupied by the air inside the balloon decreases. This is accompanied by an increase in the pressure exerted by the air on the balloon, as a consequence of Boyle’s law. As the balloon is squeezed further, the increasing pressure eventually pops it. An illustration describing the increase in pressure that accompanies a decrease in the volume of a gas is provided below.
#3. See Boyle's Law examples....
Just a thought for you to consider......
BOB RENTON
Like I said...mainly academic. Most people aren't going to notice any differences or be able to measure any differences.Item #1. Heat isolation....depending on what it is made from....the R value or resistance to heat transfer.
Item #2. It creates a larger pressure drop and REDUCTION of flow velocity of the exiting fuel mixture which actually hinders flow due to the expansion factor....Boyals Law of pressure volume temperature relationships. Applies to fuel induction systems also.....
As per Boyle’s law, any change in the volume occupied by a gas (at constant quantity and temperature) will result in a change in the pressure exerted by it. In other words, the product of the initial pressure and the initial volume of a gas is equal to the product of its final pressure and final volume (at constant temperature and number of moles). This law can be expressed mathematically as follows:
P1V1 = P2V2
Where,
P1 is the initial pressure exerted by the gas
This expression can be obtained from the pressure-volume relationship suggested by Boyle’s law. For a fixed amount of gas kept at a constant temperature, PV = k. Therefore,
- V1 is the initial volume occupied by the gas
- P2 is the final pressure exerted by the gas
- V2 is the final volume occupied by the gas
P1V1 = k (initial pressure * initial volume)
P2V2 = k (final pressure * final volume)
∴ P1V1 = P2V2
This equation can be used to predict the increase in the pressure exerted by a gas on the walls of its container when the volume of its container is decreased (and its quantity and absolute temperature remain unchanged).
Examples of Boyle’s Law
When a filled balloon is squeezed, the volume occupied by the air inside the balloon decreases. This is accompanied by an increase in the pressure exerted by the air on the balloon, as a consequence of Boyle’s law. As the balloon is squeezed further, the increasing pressure eventually pops it. An illustration describing the increase in pressure that accompanies a decrease in the volume of a gas is provided below.
#3. See Boyle's Law examples....
Just a thought for you to consider......
BOB RENTON
Choke is electric. It’s the massive leaking that bothered me.That’s a base gasket not a spacer. And yes, you need that. The choke won’t be set right with out it.
Well I torqued everything correctly and it just blew loads of fuel out the base
Holley says 108-12 “Base Gasket 1.75 in. Bore Size .3125 in. Thickness Fits Holley 4160/4150 and four barrel TBI flange pattern”What is the thickness of the carb base gasket you removed? The one you linked above is a 1/2" thick.
Also, did the air cleaner fit in the Ram Charger ductwork correctly?
Did you measure the one you removed?Holley says 108-12 “Base Gasket 1.75 in. Bore Size .3125 in. Thickness Fits Holley 4160/4150 and four barrel TBI flange pattern”
Yes I completely rebuilt the carb with all new Holley parts and set the floats.
Yes this is exactly it.Did you measure the one you removed?
Too bad you did not complete your MSAE credentials.....sometimes it takes more guts than than the glory...the hours can be difficult.....I had/hold a BS EE, an MS in Buisiness Administration-Macro Economics and a Professional Electrical Engineer credential. I have done ASME Section VIII Division 2 Unfired pressure vessel calcs, of the 3 types of gas-gas, gas to liquid, and liquid to liquid high temp heat exchangers, i held a class 2 ASME inspection credential, to be able to read and sign off "the shooter's sheets" for x-ray inspections. I have done WPS designs AND PQR records for welders' fabricated construction of ASME vessels. I've used exotic metals....Inconel, Incaloy, all the stainless steels both ferritic and non ferritic alloys (400 series of metal...iron and chrome, no nickel) I have 50+ years maintenance and supervision experience at a chemical plant and project management and have had direct responsibility for building several plants both in the US plus UK......it sounds as if we have common goals and experiences......congratulations on your achievements. ........cheers....Like I said...mainly academic. Most people aren't going to notice any differences or be able to measure any differences.
My BSME and MSME work were in fluid and thermal sciences, as well as aerodynamics. I've been in the aerospace industry for more than 44 years and I'm looking forward to retirement. I did not complete my MSAE work/thesis and do not intend to do so. Also, I have no intention of teaching master's level engineering courses ever again. I did that for one full year around 20 years ago. Maybe 2 out of 20 students were serious about having a deeper understanding of physics and engineering. Maybe.
I'll be in the garage, as well as enjoying the great outdoors much more starting sometime next month.
I'll try to do some moderating too.