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Switched source isn't good enough for EFI? Lol

Here's the simplified version;
20240610_145238.jpg
 
Here's the simplified version;
View attachment 1677328

Lightbulb moment.
I was just here talking to somebody wondering if I had the function of the brown wire wrong. I assumed the brown wire had power coming from the resistor and going somewhere. Then we talked it through.
So:
The brown wire feeds the blue wire that it's connected to during cranking. During run time, that wire does nothing and the blue wire gets power from the other side of the resistor. In this case, my black wire.
Did I get it right??

You, sir, are a scholar and a gentleman LoL
 
Lightbulb moment.
I was just here talking to somebody wondering if I had the function of the brown wire wrong. I assumed the brown wire had power coming from the resistor and going somewhere. Then we talked it through.
So:
The brown wire feeds the blue wire that it's connected to during cranking. During run time, that wire does nothing and the blue wire gets power from the other side of the resistor. In this case, my black wire.
Did I get it right??

You, sir, are a scholar and a gentleman LoL
You nailed it.
And thanks, didn't get great grades, but my friends seem to like me :)
 
Here's the simplified version;
View attachment 1677328

:bananadance:⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️




Lightbulb moment.
I was just here talking to somebody wondering if I had the function of the brown wire wrong. I assumed the brown wire had power coming from the resistor and going somewhere. Then we talked it through.
So:
The brown wire feeds the blue wire that it's connected to during cranking. During run time, that wire does nothing and the blue wire gets power from the other side of the resistor. In this case, my black wire.
Did I get it right??

You, sir, are a scholar and a gentleman LoL


As the diagram shows

Ballast gets two wires energized from Ign switch, one blue while key is in RUN and brown just cranking. And just one of them running to coil which is blue, spliced into the brown.

When key is in RUN, the blue wire feeds the ballast, and the wire to coil (also blue but on the other side of the ballast) gets powered THROUGHT the ballast, so a lower voltage rate.

When cranking, the ign switch feeds the brown wire, not anymore the blue RUN circuit. Since the blue wire to coil is spliced on the brown wire, it means the ign switch will feed the coil STRAIGHT from that splice, bypassing the ballast.

On both stages both sides of the ballast are energized since all are tied together thanks to the ballast itself, the difference is which side is feeded from ign switch and running to coil, making the opposite side to get energized with a lower voltage rate
 
Lightbulb moment.
I was just here talking to somebody wondering if I had the function of the brown wire wrong. I assumed the brown wire had power coming from the resistor and going somewhere. Then we talked it through.
So:
The brown wire feeds the blue wire that it's connected to during cranking. During run time, that wire does nothing and the blue wire gets power from the other side of the resistor. In this case, my black wire.
Did I get it right??

You, sir, are a scholar and a gentleman LoL
PM Sent
 
For anyone reading this, my diagram above was completely wrong. It should be as follows. I'll be doing a complete write up on this installation process, as soon as it's done and running. Maybe it will be easier for the next person, as opposed to reading over multiple threads/opinions/etc.

Power HOW.jpg
 
I installed EFI years ago, with it I installed Positive and Negative hubs.

Negative hub under the dash, Positive hub under the dash, both IGN and RUN connected here, along with EFI and Coil/Distributor.
Negative hub next to the battery with 1 wire to the battery neg.
Grounded everything to one of said Negative hubs, including the tbs, alternator, etc.
 
I made some time ago a full expanded version of the circuits being feeded from the ign switch on both stages ( including accs, fusebox, etc... ), but decided to make a simplified version now. Maybe this is more "selfexplained" diagram ?

ing1&2power.jpg
 
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